arithmétique prépa recueilchapitre 1problème 1.3récurrence
A divisibility by 3^(n+1)
Recueil COMIMa — Techniques de résolution de problèmes · 2026 · Madagascar · ★★★★★
Statement
Montrez que $3^{n+1}$ divise $2^{3^n} + 1$ pour tout entier $n \geq 0$.
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Origin : Recueil COMIMa — Techniques de résolution de problèmes · 2026 · Madagascar
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